7a^+32=7-40a

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Solution for 7a^+32=7-40a equation: 



7a^+32=7-40a

We move all terms to the left:

7a^+32-(7-40a)=0

We add all the numbers together, and all the variables

7a^-(-40a+7)+32=0

We add all the numbers together, and all the variables

7a-(-40a+7)+32=0

We get rid of parentheses

7a+40a-7+32=0

We add all the numbers together, and all the variables

47a+25=0

We move all terms containing a to the left, all other terms to the right

47a=-25

a=-25/47

a=-25/47

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